What are the solutions to the equation (1-x)(3-x)-8=0 ?

The solutions to the equation (1-x)(3-x)-8=0 are x=5,x=-1

Find the zeros of (1-x)(3-x)-8=0

The zeros of (1-x)(3-x)-8=0 are x=5,x=-1

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(1 - x) (3 - x) - 8 = 0

x = 5, x = - 1

Solution steps

(1 - x) (3 - x) - 8 = 0

Expand

(1 - x) (3 - x) - 8 : x^{2} - 4 x - 5

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x, x^{2} - 4 x - 3 = 0

7 x^{2} + 84 x + 247

c^{2} - 2 c = 0

(2 x - 5)^{2} + 4 x = 12

5 q^{2} + 12 q + 5 = 2 q^{2}

What are the solutions to the equation (1-x)(3-x)-8=0 ?
The solutions to the equation (1-x)(3-x)-8=0 are x=5,x=-1
Find the zeros of (1-x)(3-x)-8=0
The zeros of (1-x)(3-x)-8=0 are x=5,x=-1