What are the solutions to the equation y^2+6y+25=0 ?

The solutions to the equation y^2+6y+25=0 are y=-3+4i,y=-3-4i

Find the zeros of y^2+6y+25=0

The zeros of y^2+6y+25=0 are y=-3+4i,y=-3-4i

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y^{2} + 6 y + 25 = 0

y = - 3 + 4 i, y = - 3 - 4 i

Solution steps

y^{2} + 6 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

y_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, y_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

y = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

y = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

y = - 3 + 4 i, y = - 3 - 4 i

x, 3 x^{2} - 8 x - 16 = 0

x^{2} - x (3 x + 1) = 3

6 x^{2} - 72 x + 162 = 0

3 y^{2} - 4 = 0

3 x^{2} - 23 x + 1 = 0

What are the solutions to the equation y^2+6y+25=0 ?
The solutions to the equation y^2+6y+25=0 are y=-3+4i,y=-3-4i
Find the zeros of y^2+6y+25=0
The zeros of y^2+6y+25=0 are y=-3+4i,y=-3-4i