What are the solutions to the equation (x+1/7)(x-3/7)=0 ?

The solutions to the equation (x+1/7)(x-3/7)=0 are x=-1/7 ,x= 3/7

Find the zeros of (x+1/7)(x-3/7)=0

The zeros of (x+1/7)(x-3/7)=0 are x=-1/7 ,x= 3/7

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(x + \frac{1}{7}) (x - \frac{3}{7}) = 0

x = - \frac{1}{7}, x = \frac{3}{7}

Decimal Notation

x = - 0.14285 \dots, x = 0.42857 \dots

Solution steps

(x + \frac{1}{7}) (x - \frac{3}{7}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + \frac{1}{7} = 0 or x - \frac{3}{7} = 0

Solve

x + \frac{1}{7} = 0 : x = - \frac{1}{7}

Solve

x - \frac{3}{7} = 0 : x = \frac{3}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{7}, x = \frac{3}{7}

x, x^{2} - 10 x y + y^{2} + x + y + 1 = 0

x^{2} - 5 x - 13 = 0

9 x^{2} - 82 x + 9 = 0

5 x^{2} - 4 = - 8

2 = (1 - 2 (5) + 5) t^{2} + (2 (5) - 2 (1)) t + 1

What are the solutions to the equation (x+1/7)(x-3/7)=0 ?
The solutions to the equation (x+1/7)(x-3/7)=0 are x=-1/7 ,x= 3/7
Find the zeros of (x+1/7)(x-3/7)=0
The zeros of (x+1/7)(x-3/7)=0 are x=-1/7 ,x= 3/7