What are the solutions to the equation x^2+8x-18=0 ?

The solutions to the equation x^2+8x-18=0 are x=-4+sqrt(34),x=-4-sqrt(34)

Find the zeros of x^2+8x-18=0

The zeros of x^2+8x-18=0 are x=-4+sqrt(34),x=-4-sqrt(34)

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x^{2} + 8 x - 18 = 0

x = - 4 + 34, x = - 4 - 34

Decimal Notation

x = 1.83095 \dots, x = - 9.83095 \dots

Solution steps

x^{2} + 8 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 18) = 234

x_{1, 2} = \frac{- 8 \pm 2 34}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 34}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 34}{2 \cdot 1}

x = \frac{- 8 + 2 34}{2 \cdot 1} : - 4 + 34

x = \frac{- 8 - 2 34}{2 \cdot 1} : - 4 - 34

The solutions to the quadratic equation are:

x = - 4 + 34, x = - 4 - 34

(x - 1)^{2} = 12

x^{2} + 2 x - 1

x^{2} - 4

x^{2} - 9

x^{2} + 12 x + 48 = 0

What are the solutions to the equation x^2+8x-18=0 ?
The solutions to the equation x^2+8x-18=0 are x=-4+sqrt(34),x=-4-sqrt(34)
Find the zeros of x^2+8x-18=0
The zeros of x^2+8x-18=0 are x=-4+sqrt(34),x=-4-sqrt(34)