What are the solutions to the equation -6x^2+222x+1=1873 ?

The solutions to the equation -6x^2+222x+1=1873 are x=13,x=24

Find the zeros of -6x^2+222x+1=1873

The zeros of -6x^2+222x+1=1873 are x=13,x=24

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- 6 x^{2} + 222 x + 1 = 1873

x = 13, x = 24

Solution steps

- 6 x^{2} + 222 x + 1 = 1873

Move

1873

to the left side

- 6 x^{2} + 222 x - 1872 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 222 \pm 22 2 ^{2} - 4 ( - 6 ) ( - 1872 )}{2 ( - 6 )}

22 2^{2} - 4 (- 6) (- 1872) = 66

x_{1, 2} = \frac{- 222 \pm 66}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 222 + 66}{2 ( - 6 )}, x_{2} = \frac{- 222 - 66}{2 ( - 6 )}

x = \frac{- 222 + 66}{2 ( - 6 )} : 13

x = \frac{- 222 - 66}{2 ( - 6 )} : 24

The solutions to the quadratic equation are:

x = 13, x = 24

15 x^{2} + 29 x - 14 = 0

(x - 2)^{2} = 2

4 x^{2} + 10 x - 14 = 0

r^{2} + 2 r + 32 = 0

x^{2} + 2 x - 8 = 0

What are the solutions to the equation -6x^2+222x+1=1873 ?
The solutions to the equation -6x^2+222x+1=1873 are x=13,x=24
Find the zeros of -6x^2+222x+1=1873
The zeros of -6x^2+222x+1=1873 are x=13,x=24