What are the solutions to the equation 3(x-2)^2+3=6x-12 ?

The solutions to the equation 3(x-2)^2+3=6x-12 are x=3

Find the zeros of 3(x-2)^2+3=6x-12

The zeros of 3(x-2)^2+3=6x-12 are x=3

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3 (x - 2)^{2} + 3 = 6 x - 12

x = 3

Solution steps

3 (x - 2)^{2} + 3 = 6 x - 12

Expand

3 (x - 2)^{2} + 3 : 3 x^{2} - 12 x + 15

3 x^{2} - 12 x + 15 = 6 x - 12

Move

12

to the left side

3 x^{2} - 12 x + 27 = 6 x

Move

6 x

to the left side

3 x^{2} - 18 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 27 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 3}

x = \frac{- ( - 18 )}{2 \cdot 3}

\frac{- ( - 18 )}{2 \cdot 3} = 3

x = 3

The solution to the quadratic equation is:

x = 3

3 x^{2} - 6 x + 2 = 0

x^{2} - 11 x - 80 = 0

f, y = (f)^{2}

2 x^{2} + 12 x + 5 = 0

1 0^{2} = 5^{2} + x^{2}

What are the solutions to the equation 3(x-2)^2+3=6x-12 ?
The solutions to the equation 3(x-2)^2+3=6x-12 are x=3
Find the zeros of 3(x-2)^2+3=6x-12
The zeros of 3(x-2)^2+3=6x-12 are x=3