What are the solutions to the equation 8x-x^2=12 ?

The solutions to the equation 8x-x^2=12 are x=2,x=6

Find the zeros of 8x-x^2=12

The zeros of 8x-x^2=12 are x=2,x=6

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8 x - x^{2} = 12

x = 2, x = 6

Solution steps

8 x - x^{2} = 12

Move

12

to the left side

8 x - x^{2} - 12 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 12 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 12) = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 ( - 1 )}, x_{2} = \frac{- 8 - 4}{2 ( - 1 )}

x = \frac{- 8 + 4}{2 ( - 1 )} : 2

x = \frac{- 8 - 4}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 2, x = 6

5 x^{2} + 35 x - 90 = 0

15 x + 15 = - 4 x^{2}

4 x^{2} + 12 x + 9 = 0

x^{2} - 4 x + 2 = 0

(x - 3)^{2} - 169 = 0

What are the solutions to the equation 8x-x^2=12 ?
The solutions to the equation 8x-x^2=12 are x=2,x=6
Find the zeros of 8x-x^2=12
The zeros of 8x-x^2=12 are x=2,x=6