What are the solutions to the equation 2x^2+28x+98=-200 ?

The solutions to the equation 2x^2+28x+98=-200 are x=-7+10i,x=-7-10i

Find the zeros of 2x^2+28x+98=-200

The zeros of 2x^2+28x+98=-200 are x=-7+10i,x=-7-10i

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2 x^{2} + 28 x + 98 = - 200

x = - 7 + 10 i, x = - 7 - 10 i

Solution steps

2 x^{2} + 28 x + 98 = - 200

Move

200

to the left side

2 x^{2} + 28 x + 298 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 2 \cdot 298}{2 \cdot 2}

Simplify

2 8^{2} - 4 \cdot 2 \cdot 298 : 40 i

x_{1, 2} = \frac{- 28 \pm 40 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 28 + 40 i}{2 \cdot 2}, x_{2} = \frac{- 28 - 40 i}{2 \cdot 2}

x = \frac{- 28 + 40 i}{2 \cdot 2} : - 7 + 10 i

x = \frac{- 28 - 40 i}{2 \cdot 2} : - 7 - 10 i

The solutions to the quadratic equation are:

x = - 7 + 10 i, x = - 7 - 10 i

x^{2} - 7 x + 24 = 12

9 - 4 y^{2} = 57

- 2 x^{2} + 7 x = 0

x^{2} + (1 + x)^{2} = - \frac{( x - 1 )}{2}

(z - 1)^{2} = 0

What are the solutions to the equation 2x^2+28x+98=-200 ?
The solutions to the equation 2x^2+28x+98=-200 are x=-7+10i,x=-7-10i
Find the zeros of 2x^2+28x+98=-200
The zeros of 2x^2+28x+98=-200 are x=-7+10i,x=-7-10i