What are the solutions to the equation 2X^2+4X-6=0 ?

The solutions to the equation 2X^2+4X-6=0 are X=1,X=-3

Find the zeros of 2X^2+4X-6=0

The zeros of 2X^2+4X-6=0 are X=1,X=-3

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2 X^{2} + 4 X - 6 = 0

X = 1, X = - 3

Solution steps

2 X^{2} + 4 X - 6 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 6) = 8

X_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 4 + 8}{2 \cdot 2}, X_{2} = \frac{- 4 - 8}{2 \cdot 2}

X = \frac{- 4 + 8}{2 \cdot 2} : 1

X = \frac{- 4 - 8}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

X = 1, X = - 3

8 x^{2} = - 4 x

x, x^{2} + y^{2} - 4 x + 2 y + 14 = 0

x, (x + 1)^{2} + (y - 3)^{2} = 0

2 x^{2} + 13 x + 20

225 = x^{2}

What are the solutions to the equation 2X^2+4X-6=0 ?
The solutions to the equation 2X^2+4X-6=0 are X=1,X=-3
Find the zeros of 2X^2+4X-6=0
The zeros of 2X^2+4X-6=0 are X=1,X=-3