What are the solutions to the equation 4+5z-6z^2=0 ?

The solutions to the equation 4+5z-6z^2=0 are z=-1/2 ,z= 4/3

Find the zeros of 4+5z-6z^2=0

The zeros of 4+5z-6z^2=0 are z=-1/2 ,z= 4/3

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4 + 5 z - 6 z^{2} = 0

z = - \frac{1}{2}, z = \frac{4}{3}

Decimal Notation

z = - 0.5, z = 1.33333 \dots

Solution steps

4 + 5 z - 6 z^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 z^{2} + 5 z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 6 ) \cdot 4}{2 ( - 6 )}

5^{2} - 4 (- 6) \cdot 4 = 11

z_{1, 2} = \frac{- 5 \pm 11}{2 ( - 6 )}

Separate the solutions

z_{1} = \frac{- 5 + 11}{2 ( - 6 )}, z_{2} = \frac{- 5 - 11}{2 ( - 6 )}

z = \frac{- 5 + 11}{2 ( - 6 )} : - \frac{1}{2}

z = \frac{- 5 - 11}{2 ( - 6 )} : \frac{4}{3}

The solutions to the quadratic equation are:

z = - \frac{1}{2}, z = \frac{4}{3}

\frac{( x ^{2} + 3 )}{2} = 14

s^{2} + 4

2^{2} + b^{2} = 7^{2}

- 6 x^{2} + 18 x + 29 = 0

7 x^{2} - 9 x = 3 x

What are the solutions to the equation 4+5z-6z^2=0 ?
The solutions to the equation 4+5z-6z^2=0 are z=-1/2 ,z= 4/3
Find the zeros of 4+5z-6z^2=0
The zeros of 4+5z-6z^2=0 are z=-1/2 ,z= 4/3