What are the solutions to the equation 3y^2-6y=8 ?

The solutions to the equation 3y^2-6y=8 are y=(3+sqrt(33))/3 ,y=(3-sqrt(33))/3

Find the zeros of 3y^2-6y=8

The zeros of 3y^2-6y=8 are y=(3+sqrt(33))/3 ,y=(3-sqrt(33))/3

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3 y^{2} - 6 y = 8

y = \frac{3 + 33}{3}, y = \frac{3 - 33}{3}

Decimal Notation

y = 2.91485 \dots, y = - 0.91485 \dots

Solution steps

3 y^{2} - 6 y = 8

Move

8

to the left side

3 y^{2} - 6 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 8) = 233

y_{1, 2} = \frac{- ( - 6 ) \pm 2 33}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 33}{2 \cdot 3}, y_{2} = \frac{- ( - 6 ) - 2 33}{2 \cdot 3}

y = \frac{- ( - 6 ) + 2 33}{2 \cdot 3} : \frac{3 + 33}{3}

y = \frac{- ( - 6 ) - 2 33}{2 \cdot 3} : \frac{3 - 33}{3}

The solutions to the quadratic equation are:

y = \frac{3 + 33}{3}, y = \frac{3 - 33}{3}

x^{2} - 11 x + 26 = 0

2 x^{2} - 5 = 11

3 x^{2} + 17 x - 46 = 0

t^{2} - t - 1 = 0

2 x^{2} - 3 x = 6

What are the solutions to the equation 3y^2-6y=8 ?
The solutions to the equation 3y^2-6y=8 are y=(3+sqrt(33))/3 ,y=(3-sqrt(33))/3
Find the zeros of 3y^2-6y=8
The zeros of 3y^2-6y=8 are y=(3+sqrt(33))/3 ,y=(3-sqrt(33))/3