What are the solutions to the equation 2x^2+172=-40x ?

The solutions to the equation 2x^2+172=-40x are x=-10+sqrt(14),x=-10-sqrt(14)

Find the zeros of 2x^2+172=-40x

The zeros of 2x^2+172=-40x are x=-10+sqrt(14),x=-10-sqrt(14)

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2 x^{2} + 172 = - 40 x

x = - 10 + 14, x = - 10 - 14

Decimal Notation

x = - 6.25834 \dots, x = - 13.74165 \dots

Solution steps

2 x^{2} + 172 = - 40 x

Move

40 x

to the left side

2 x^{2} + 172 + 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 40 x + 172 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 2 \cdot 172}{2 \cdot 2}

4 0^{2} - 4 \cdot 2 \cdot 172 = 414

x_{1, 2} = \frac{- 40 \pm 4 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 40 + 4 14}{2 \cdot 2}, x_{2} = \frac{- 40 - 4 14}{2 \cdot 2}

x = \frac{- 40 + 4 14}{2 \cdot 2} : - 10 + 14

x = \frac{- 40 - 4 14}{2 \cdot 2} : - 10 - 14

The solutions to the quadratic equation are:

x = - 10 + 14, x = - 10 - 14

x^{2} + 4 x - 1

6 x^{2} + 6 = 246

x^{2} - 3 x + 2.25 = 0

11 e^{2} + 7 = 106

s^{2} + 2 s + 4

What are the solutions to the equation 2x^2+172=-40x ?
The solutions to the equation 2x^2+172=-40x are x=-10+sqrt(14),x=-10-sqrt(14)
Find the zeros of 2x^2+172=-40x
The zeros of 2x^2+172=-40x are x=-10+sqrt(14),x=-10-sqrt(14)