What is solvefor E,y^2-2yE-x^2+2xE<= 0 ?

The solution to solvefor E,y^2-2yE-x^2+2xE<= 0 is E<= (x+y)/2 ;\quad y<x

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solvefor E,y^2-2yE-x^2+2xE<= 0

solve for

E, y^{2} - 2 y E - x^{2} + 2 x E \leq 0

E \leq \frac{x + y}{2}; y < x

Solution steps

y^{2} - 2 y E - x^{2} + 2 x E \leq 0

Move

y^{2}

to the right side

- 2 y E - x^{2} + 2 x E \leq - y^{2}

Move

x^{2}

to the right side

- 2 y E + 2 x E \leq - y^{2} + x^{2}

Factor

- 2 y E + 2 x E : 2 E (- y + x)

2 E (- y + x) \leq - y^{2} + x^{2}

Divide both sides by

2 (- y + x); y < x

E \leq \frac{x + y}{2}; y < x

4 k^{2} + 7 jk - 2 j^{2}

\frac{8 x + 7}{6} + \frac{3 - 2 x}{4} - \frac{5 x - 2}{2} = 32

∣ 2 x - 1 ∣ - 5 = 0

3 x^{2} - 18 x + 1 = 7 x - 7

20 x^{3} y^{2} + 15 x^{2} y^{3}

What is solvefor E,y^2-2yE-x^2+2xE<= 0 ?
The solution to solvefor E,y^2-2yE-x^2+2xE<= 0 is E<= (x+y)/2 ;\quad y<x