What are the solutions to the equation p^2-10=-3p ?

The solutions to the equation p^2-10=-3p are p=2,p=-5

Find the zeros of p^2-10=-3p

The zeros of p^2-10=-3p are p=2,p=-5

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p^{2} - 10 = - 3 p

p = 2, p = - 5

Solution steps

p^{2} - 10 = - 3 p

Move

3 p

to the left side

p^{2} - 10 + 3 p = 0

Write in the standard form

a x^{2} + b x + c = 0

p^{2} + 3 p - 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

p_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 3 + 7}{2 \cdot 1}, p_{2} = \frac{- 3 - 7}{2 \cdot 1}

p = \frac{- 3 + 7}{2 \cdot 1} : 2

p = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

p = 2, p = - 5

9 x^{2} + 5 x - 9 = 0

11 x^{2} - 13 x = 8 x - 3 x^{2}

x^{2} - 21 = 100

2 x^{2} - 3 = 5

(x + 3) (x + 3) = 0

What are the solutions to the equation p^2-10=-3p ?
The solutions to the equation p^2-10=-3p are p=2,p=-5
Find the zeros of p^2-10=-3p
The zeros of p^2-10=-3p are p=2,p=-5