What are the solutions to the equation x^2+10x+19=0 ?

The solutions to the equation x^2+10x+19=0 are x=-5+sqrt(6),x=-5-sqrt(6)

Find the zeros of x^2+10x+19=0

The zeros of x^2+10x+19=0 are x=-5+sqrt(6),x=-5-sqrt(6)

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x^{2} + 10 x + 19 = 0

x = - 5 + 6, x = - 5 - 6

Decimal Notation

x = - 2.55051 \dots, x = - 7.44948 \dots

Solution steps

x^{2} + 10 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 19 = 26

x_{1, 2} = \frac{- 10 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 6}{2 \cdot 1}

x = \frac{- 10 + 2 6}{2 \cdot 1} : - 5 + 6

x = \frac{- 10 - 2 6}{2 \cdot 1} : - 5 - 6

The solutions to the quadratic equation are:

x = - 5 + 6, x = - 5 - 6

(x - 6)^{2} = - 81

n^{2} = 9

- 3 x^{2} + 3 x + 5 = 0

x, z = 2 - x^{2} - y^{2}

x^{2} - 4 x + 8 = 2 - 2 x^{2}

What are the solutions to the equation x^2+10x+19=0 ?
The solutions to the equation x^2+10x+19=0 are x=-5+sqrt(6),x=-5-sqrt(6)
Find the zeros of x^2+10x+19=0
The zeros of x^2+10x+19=0 are x=-5+sqrt(6),x=-5-sqrt(6)