What are the solutions to the equation 3x^2+48x+183=0 ?

The solutions to the equation 3x^2+48x+183=0 are x=-8+sqrt(3),x=-8-sqrt(3)

Find the zeros of 3x^2+48x+183=0

The zeros of 3x^2+48x+183=0 are x=-8+sqrt(3),x=-8-sqrt(3)

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3 x^{2} + 48 x + 183 = 0

x = - 8 + 3, x = - 8 - 3

Decimal Notation

x = - 6.26794 \dots, x = - 9.73205 \dots

Solution steps

3 x^{2} + 48 x + 183 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 3 \cdot 183}{2 \cdot 3}

4 8^{2} - 4 \cdot 3 \cdot 183 = 63

x_{1, 2} = \frac{- 48 \pm 6 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 48 + 6 3}{2 \cdot 3}, x_{2} = \frac{- 48 - 6 3}{2 \cdot 3}

x = \frac{- 48 + 6 3}{2 \cdot 3} : - 8 + 3

x = \frac{- 48 - 6 3}{2 \cdot 3} : - 8 - 3

The solutions to the quadratic equation are:

x = - 8 + 3, x = - 8 - 3

x^{2} - 2 x - 3 = 0

2 x^{2} + 5 x + 3 = 0

x (2 x - 3) = 0

2 y^{2} + 12 y - 224 = 0

x, f = in (x^{2} + 7)

What are the solutions to the equation 3x^2+48x+183=0 ?
The solutions to the equation 3x^2+48x+183=0 are x=-8+sqrt(3),x=-8-sqrt(3)
Find the zeros of 3x^2+48x+183=0
The zeros of 3x^2+48x+183=0 are x=-8+sqrt(3),x=-8-sqrt(3)