What are the solutions to the equation solvefor x,y=(x-2)^2 ?

The solutions to the equation solvefor x,y=(x-2)^2 are x=sqrt(y)+2,x=-sqrt(y)+2

Find the zeros of solvefor x,y=(x-2)^2

The zeros of solvefor x,y=(x-2)^2 are x=sqrt(y)+2,x=-sqrt(y)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, y = (x - 2)^{2}

x = y + 2, x = - y + 2

Solution steps

y = (x - 2)^{2}

Switch sides

(x - 2)^{2} = y

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = y : x = y + 2

Solve

x - 2 = - y : x = - y + 2

The solutions to the quadratic equation are:

x = y + 2, x = - y + 2

x^{2} + 3 x = 2 (1 - x^{2})

9 x^{2} - 6 x + 1 = 7

2 x^{2} = 3 x + 20

x^{2} + 6 x - 1

x, x^{2} y^{2} = 9

What are the solutions to the equation solvefor x,y=(x-2)^2 ?
The solutions to the equation solvefor x,y=(x-2)^2 are x=sqrt(y)+2,x=-sqrt(y)+2
Find the zeros of solvefor x,y=(x-2)^2
The zeros of solvefor x,y=(x-2)^2 are x=sqrt(y)+2,x=-sqrt(y)+2