What are the solutions to the equation 5x^2-10x-8=0 ?

The solutions to the equation 5x^2-10x-8=0 are x=(5+sqrt(65))/5 ,x=(5-sqrt(65))/5

Find the zeros of 5x^2-10x-8=0

The zeros of 5x^2-10x-8=0 are x=(5+sqrt(65))/5 ,x=(5-sqrt(65))/5

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5 x^{2} - 10 x - 8 = 0

x = \frac{5 + 65}{5}, x = \frac{5 - 65}{5}

Decimal Notation

x = 2.61245 \dots, x = - 0.61245 \dots

Solution steps

5 x^{2} - 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 (- 8) = 265

x_{1, 2} = \frac{- ( - 10 ) \pm 2 65}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 65}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 2 65}{2 \cdot 5}

x = \frac{- ( - 10 ) + 2 65}{2 \cdot 5} : \frac{5 + 65}{5}

x = \frac{- ( - 10 ) - 2 65}{2 \cdot 5} : \frac{5 - 65}{5}

The solutions to the quadratic equation are:

x = \frac{5 + 65}{5}, x = \frac{5 - 65}{5}

y, 2 x^{2} y + \frac{( x ^{3} - y ^{2} )}{x} + 3 = 0

- x^{2} + 3 x + 1 = 0

x^{2} - 10 x + 24

x^{2} + 1.3 x = 0

s^{2} + 4 s + 10 = 0

What are the solutions to the equation 5x^2-10x-8=0 ?
The solutions to the equation 5x^2-10x-8=0 are x=(5+sqrt(65))/5 ,x=(5-sqrt(65))/5
Find the zeros of 5x^2-10x-8=0
The zeros of 5x^2-10x-8=0 are x=(5+sqrt(65))/5 ,x=(5-sqrt(65))/5