What are the solutions to the equation u^2-10u+25=0 ?

The solutions to the equation u^2-10u+25=0 are u=5

Find the zeros of u^2-10u+25=0

The zeros of u^2-10u+25=0 are u=5

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u^{2} - 10 u + 25 = 0

u = 5

Solution steps

u^{2} - 10 u + 25 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

u_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

u = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

u = 5

The solution to the quadratic equation is:

u = 5

5 x^{2} = 8 x - 8

y^{2} + 2 y - 35 = 0

(x + 6)^{2} = 81

(5 x - 7)^{2} - 1 = 8

5 x^{2} - 3125 = 0

What are the solutions to the equation u^2-10u+25=0 ?
The solutions to the equation u^2-10u+25=0 are u=5
Find the zeros of u^2-10u+25=0
The zeros of u^2-10u+25=0 are u=5