What are the solutions to the equation 12x^2-75=0 ?

The solutions to the equation 12x^2-75=0 are x= 5/2 ,x=-5/2

Find the zeros of 12x^2-75=0

The zeros of 12x^2-75=0 are x= 5/2 ,x=-5/2

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12 x^{2} - 75 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

12 x^{2} - 75 = 0

Move

75

to the right side

12 x^{2} = 75

Divide both sides by

12

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

x^{2} + 4 x + 3 = 0

25 x^{2} + 2 (x - 4)^{2} = - 3

x, x^{2} + 5 x y - 2 y = 12

16 x^{2} = 2 x

x^{2} - 20 x + 100 = x + 2

What are the solutions to the equation 12x^2-75=0 ?
The solutions to the equation 12x^2-75=0 are x= 5/2 ,x=-5/2
Find the zeros of 12x^2-75=0
The zeros of 12x^2-75=0 are x= 5/2 ,x=-5/2