What are the solutions to the equation x(x-16)-20=-3 ?

The solutions to the equation x(x-16)-20=-3 are x=17,x=-1

Find the zeros of x(x-16)-20=-3

The zeros of x(x-16)-20=-3 are x=17,x=-1

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x (x - 16) - 20 = - 3

x = 17, x = - 1

Solution steps

x (x - 16) - 20 = - 3

Expand

x (x - 16) - 20 : x^{2} - 16 x - 20

x^{2} - 16 x - 20 = - 3

Move

3

to the left side

x^{2} - 16 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 17) = 18

x_{1, 2} = \frac{- ( - 16 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 18}{2 \cdot 1}

x = \frac{- ( - 16 ) + 18}{2 \cdot 1} : 17

x = \frac{- ( - 16 ) - 18}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 17, x = - 1

4^{2} + b^{2} = 8^{2}

r, y = π r^{2}

(x - 3)^{2} + (x + 1)^{2} = 12

9 x^{2} = 30 x - 26

x, (x + 2)^{2} = 8 (y + 2)^{2}

What are the solutions to the equation x(x-16)-20=-3 ?
The solutions to the equation x(x-16)-20=-3 are x=17,x=-1
Find the zeros of x(x-16)-20=-3
The zeros of x(x-16)-20=-3 are x=17,x=-1