What are the solutions to the equation (x+5)(x+9)=20 ?

The solutions to the equation (x+5)(x+9)=20 are x=-7+2sqrt(6),x=-7-2sqrt(6)

Find the zeros of (x+5)(x+9)=20

The zeros of (x+5)(x+9)=20 are x=-7+2sqrt(6),x=-7-2sqrt(6)

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(x + 5) (x + 9) = 20

x = - 7 + 26, x = - 7 - 26

Decimal Notation

x = - 2.10102 \dots, x = - 11.89897 \dots

Solution steps

(x + 5) (x + 9) = 20

Expand

(x + 5) (x + 9) : x^{2} + 14 x + 45

x^{2} + 14 x + 45 = 20

Move

20

to the left side

x^{2} + 14 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 25 = 46

x_{1, 2} = \frac{- 14 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 6}{2 \cdot 1}

x = \frac{- 14 + 4 6}{2 \cdot 1} : - 7 + 26

x = \frac{- 14 - 4 6}{2 \cdot 1} : - 7 - 26

The solutions to the quadratic equation are:

x = - 7 + 26, x = - 7 - 26

x + 2 = 3 - 2 x^{2}

3 (x + 4)^{2} = 48

6 x^{2} - x + 1 = 0

r^{2} - 2 r + 4 = 0

s^{2} - 8 s + 20

What are the solutions to the equation (x+5)(x+9)=20 ?
The solutions to the equation (x+5)(x+9)=20 are x=-7+2sqrt(6),x=-7-2sqrt(6)
Find the zeros of (x+5)(x+9)=20
The zeros of (x+5)(x+9)=20 are x=-7+2sqrt(6),x=-7-2sqrt(6)