What are the solutions to the equation -1=x^2-2x ?

The solutions to the equation -1=x^2-2x are x=1

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-1=x^2-2x

- 1 = x^{2} - 2 x

x = 1

Solution steps

- 1 = x^{2} - 2 x

Switch sides

x^{2} - 2 x = - 1

Move

1

to the left side

x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

x = 1

The solution to the quadratic equation is:

x = 1

1000 = - 16 t^{2} + 1700

x^{2} - 10 x - 119 = 0

x^{2} + \frac{3}{4} x - 6

9 x^{2} - 3 = 897

x^{2} + 2 x + 3 x + 6 = 0

What are the solutions to the equation -1=x^2-2x ?
The solutions to the equation -1=x^2-2x are x=1
Find the zeros of -1=x^2-2x
The zeros of -1=x^2-2x are x=1