What are the solutions to the equation y^2=-8y ?

The solutions to the equation y^2=-8y are y=0,y=-8

Find the zeros of y^2=-8y

The zeros of y^2=-8y are y=0,y=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} = - 8 y

y = 0, y = - 8

Solution steps

y^{2} = - 8 y

Move

8 y

to the left side

y^{2} + 8 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

y_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 8}{2 \cdot 1}, y_{2} = \frac{- 8 - 8}{2 \cdot 1}

y = \frac{- 8 + 8}{2 \cdot 1} : 0

y = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

y = 0, y = - 8

y^{2} = - 49

x, x^{2} + y^{2} - 10 x + 2 y + 26 = 0

2 x^{2} - 5 x + 15 = 0

5 x^{2} = - 45

x^{2} + 5 x + c = 0

What are the solutions to the equation y^2=-8y ?
The solutions to the equation y^2=-8y are y=0,y=-8
Find the zeros of y^2=-8y
The zeros of y^2=-8y are y=0,y=-8