What are the solutions to the equation 2x^2+5=2x ?

The solutions to the equation 2x^2+5=2x are x= 1/2+i 3/2 ,x= 1/2-i 3/2

Find the zeros of 2x^2+5=2x

The zeros of 2x^2+5=2x are x= 1/2+i 3/2 ,x= 1/2-i 3/2

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2 x^{2} + 5 = 2 x

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

2 x^{2} + 5 = 2 x

Move

2 x

to the left side

2 x^{2} + 5 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 5 : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 2}

x = \frac{- ( - 2 ) + 6 i}{2 \cdot 2} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 2 ) - 6 i}{2 \cdot 2} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

a, a^{2} + b^{2} + c^{2} = 1

y, 2 x y + x^{3} - 3 y^{2} = 5

y^{2} + 10 y + 24 = 0

\frac{( x + 3 ) ^{2}}{81} - \frac{( x - 4 ) ^{2}}{16} = 1

- 20 x^{2} + 360 x + 1000 = 0

What are the solutions to the equation 2x^2+5=2x ?
The solutions to the equation 2x^2+5=2x are x= 1/2+i 3/2 ,x= 1/2-i 3/2
Find the zeros of 2x^2+5=2x
The zeros of 2x^2+5=2x are x= 1/2+i 3/2 ,x= 1/2-i 3/2