What are the solutions to the equation (x^2+2x+1)=0 ?

The solutions to the equation (x^2+2x+1)=0 are x=-1

Find the zeros of (x^2+2x+1)=0

The zeros of (x^2+2x+1)=0 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} + 2 x + 1) = 0

x = - 1

Solution steps

(x^{2} + 2 x + 1) = 0

Refine

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

- 16 x^{2} + 100 x + 10 = 0

x, 3 x^{2} = y^{2}

12 = x^{2} - 4

z^{2} + (3 + j) z + 1 = 0

2 x^{2} + 6 x = 36

What are the solutions to the equation (x^2+2x+1)=0 ?
The solutions to the equation (x^2+2x+1)=0 are x=-1
Find the zeros of (x^2+2x+1)=0
The zeros of (x^2+2x+1)=0 are x=-1