What are the solutions to the equation 2(x+3)^2+1=9 ?

The solutions to the equation 2(x+3)^2+1=9 are x=-1,x=-5

Find the zeros of 2(x+3)^2+1=9

The zeros of 2(x+3)^2+1=9 are x=-1,x=-5

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2 (x + 3)^{2} + 1 = 9

x = - 1, x = - 5

Solution steps

2 (x + 3)^{2} + 1 = 9

Move

1

to the right side

2 (x + 3)^{2} = 8

Divide both sides by

2

(x + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 4 : x = - 1

Solve

x + 3 = - 4 : x = - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

6 x^{2} + 1 = 0

6 x^{2} = 4 x - 9

x^{2} = 8 x - 41

2 x^{2} + 14 x + 20 = 0

x^{2} - 8 x + 22 = 0

What are the solutions to the equation 2(x+3)^2+1=9 ?
The solutions to the equation 2(x+3)^2+1=9 are x=-1,x=-5
Find the zeros of 2(x+3)^2+1=9
The zeros of 2(x+3)^2+1=9 are x=-1,x=-5