What are the solutions to the equation solvefor x,f=k(x-3)^2 ?

The solutions to the equation solvefor x,f=k(x-3)^2 are x=sqrt(f/k)+3,x=-sqrt(f/k)+3;\quad k\ne 0

Find the zeros of solvefor x,f=k(x-3)^2

The zeros of solvefor x,f=k(x-3)^2 are x=sqrt(f/k)+3,x=-sqrt(f/k)+3;\quad k\ne 0

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solve for

x, f = k (x - 3)^{2}

x = \frac{f}{k} + 3, x = - \frac{f}{k} + 3; k \neq = 0

Solution steps

f = k (x - 3)^{2}

Switch sides

k (x - 3)^{2} = f

Divide both sides by

k; k \neq = 0

(x - 3)^{2} = \frac{f}{k}; k \neq = 0

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = \frac{f}{k} : x = \frac{f}{k} + 3

Solve

x - 3 = - \frac{f}{k} : x = - \frac{f}{k} + 3

The solutions to the quadratic equation are:

x = \frac{f}{k} + 3, x = - \frac{f}{k} + 3; k \neq = 0

2 y^{2} - 2 = 0

6 x^{2} - 20 x + 5 = 0

x^{2} + 2 x + 1 = 2

y, 3 y^{2} - 6 y = 0

x^{2} + 5 x - c = 0

What are the solutions to the equation solvefor x,f=k(x-3)^2 ?
The solutions to the equation solvefor x,f=k(x-3)^2 are x=sqrt(f/k)+3,x=-sqrt(f/k)+3;\quad k\ne 0
Find the zeros of solvefor x,f=k(x-3)^2
The zeros of solvefor x,f=k(x-3)^2 are x=sqrt(f/k)+3,x=-sqrt(f/k)+3;\quad k\ne 0