What are the solutions to the equation x^2+x=72 ?

The solutions to the equation x^2+x=72 are x=8,x=-9

Find the zeros of x^2+x=72

The zeros of x^2+x=72 are x=8,x=-9

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x^{2} + x = 72

x = 8, x = - 9

Solution steps

x^{2} + x = 72

Move

72

to the left side

x^{2} + x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 1}, x_{2} = \frac{- 1 - 17}{2 \cdot 1}

x = \frac{- 1 + 17}{2 \cdot 1} : 8

x = \frac{- 1 - 17}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 8, x = - 9

- 4 = 4.2 \cdot \frac{1}{2} + b

x^{3} + 7 x^{2} - 9 x - 63

- \frac{3}{2} (1)

(x - 1)^{2} = 9

\frac{7 a}{9} - \frac{3 a}{4}

What are the solutions to the equation x^2+x=72 ?
The solutions to the equation x^2+x=72 are x=8,x=-9
Find the zeros of x^2+x=72
The zeros of x^2+x=72 are x=8,x=-9