What are the solutions to the equation x^2+13x+50=8 ?

The solutions to the equation x^2+13x+50=8 are x=-6,x=-7

Find the zeros of x^2+13x+50=8

The zeros of x^2+13x+50=8 are x=-6,x=-7

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x^{2} + 13 x + 50 = 8

x = - 6, x = - 7

Solution steps

x^{2} + 13 x + 50 = 8

Move

8

to the left side

x^{2} + 13 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 42 = 1

x_{1, 2} = \frac{- 13 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 1}{2 \cdot 1}, x_{2} = \frac{- 13 - 1}{2 \cdot 1}

x = \frac{- 13 + 1}{2 \cdot 1} : - 6

x = \frac{- 13 - 1}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 6, x = - 7

\frac{x ( x - 8 )}{4} + 2 = 0

x^{2} - 8 x + 16 = 8

10 x^{2} - 10 = 0

3 x^{2} + 5 x - 23 = 0

x^{2} - 5 x - 6 = 0

What are the solutions to the equation x^2+13x+50=8 ?
The solutions to the equation x^2+13x+50=8 are x=-6,x=-7
Find the zeros of x^2+13x+50=8
The zeros of x^2+13x+50=8 are x=-6,x=-7