What are the solutions to the equation completesquare x^2-4x-1=0 ?

The solutions to the equation completesquare x^2-4x-1=0 are x=sqrt(5)+2,x=-sqrt(5)+2

Find the zeros of completesquare x^2-4x-1=0

The zeros of completesquare x^2-4x-1=0 are x=sqrt(5)+2,x=-sqrt(5)+2

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x^{2} - 4 x - 1 = 0

x = 5 + 2, x = - 5 + 2

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

x^{2} - 4 x - 1 = 0

Move

1

to the right side

x^{2} - 4 x = 1

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 5

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 5 : x = 5 + 2

Solve

x - 2 = - 5 : x = - 5 + 2

The solutions to the quadratic equation are:

x = 5 + 2, x = - 5 + 2

x^{2} + 10 x - 8 = 0

- \frac{7}{2} x^{2} + 3 x + \frac{8}{3}

(x + 1)^{2} + 2 x = 3 x (x + 1) + 5

(x - 3)^{2} + (x - 1)^{2} = 0

x^{2} + 4 x - 17 = 0

What are the solutions to the equation completesquare x^2-4x-1=0 ?
The solutions to the equation completesquare x^2-4x-1=0 are x=sqrt(5)+2,x=-sqrt(5)+2
Find the zeros of completesquare x^2-4x-1=0
The zeros of completesquare x^2-4x-1=0 are x=sqrt(5)+2,x=-sqrt(5)+2