What are the solutions to the equation 2x(x+1)=x^2-1 ?

The solutions to the equation 2x(x+1)=x^2-1 are x=-1

Find the zeros of 2x(x+1)=x^2-1

The zeros of 2x(x+1)=x^2-1 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x (x + 1) = x^{2} - 1

x = - 1

Solution steps

2 x (x + 1) = x^{2} - 1

Expand

2 x (x + 1) : 2 x^{2} + 2 x

2 x^{2} + 2 x = x^{2} - 1

Move

1

to the left side

2 x^{2} + 2 x + 1 = x^{2}

Move

x^{2}

to the left side

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

6 x^{2} - 1 = 0

x^{2} - 63 = 0

x^{2} - 6 = 5 x

4^{2} + 2^{2} = x^{2}

z^{2} = 49

What are the solutions to the equation 2x(x+1)=x^2-1 ?
The solutions to the equation 2x(x+1)=x^2-1 are x=-1
Find the zeros of 2x(x+1)=x^2-1
The zeros of 2x(x+1)=x^2-1 are x=-1