What are the solutions to the equation 7x^2+4x-1=0 ?

The solutions to the equation 7x^2+4x-1=0 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7

Find the zeros of 7x^2+4x-1=0

The zeros of 7x^2+4x-1=0 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7

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7 x^{2} + 4 x - 1 = 0

x = \frac{- 2 + 11}{7}, x = - \frac{2 + 11}{7}

Decimal Notation

x = 0.18808 \dots, x = - 0.75951 \dots

Solution steps

7 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

4^{2} - 4 \cdot 7 (- 1) = 211

x_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 4 + 2 11}{2 \cdot 7}, x_{2} = \frac{- 4 - 2 11}{2 \cdot 7}

x = \frac{- 4 + 2 11}{2 \cdot 7} : \frac{- 2 + 11}{7}

x = \frac{- 4 - 2 11}{2 \cdot 7} : - \frac{2 + 11}{7}

The solutions to the quadratic equation are:

x = \frac{- 2 + 11}{7}, x = - \frac{2 + 11}{7}

x, x^{2} + y^{2} + z^{2} = 8

x, x^{2} + y^{2} + z^{2} = 6

(x - 4)^{2} + 8 = 0

x^{2} - 12 x - 85 = 0

4 x^{2} - 4 x - 35 = 0

What are the solutions to the equation 7x^2+4x-1=0 ?
The solutions to the equation 7x^2+4x-1=0 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7
Find the zeros of 7x^2+4x-1=0
The zeros of 7x^2+4x-1=0 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7