What are the solutions to the equation x^2+1^2=2^2 ?

The solutions to the equation x^2+1^2=2^2 are x=sqrt(3),x=-sqrt(3)

Find the zeros of x^2+1^2=2^2

The zeros of x^2+1^2=2^2 are x=sqrt(3),x=-sqrt(3)

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x^{2} + 1^{2} = 2^{2}

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

x^{2} + 1^{2} = 2^{2}

Move

1^{2}

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

2 n^{2} - 5 = - 35

10 k^{2} - 97 = 3 k^{2} + 659

(3 x + 1) 2 - 5 (x - 3) - 8 x = 9 (x^{2} + 1)

3 x^{2} = 2 x + 1

5 x^{2} + 22 x - 56 = - 8

What are the solutions to the equation x^2+1^2=2^2 ?
The solutions to the equation x^2+1^2=2^2 are x=sqrt(3),x=-sqrt(3)
Find the zeros of x^2+1^2=2^2
The zeros of x^2+1^2=2^2 are x=sqrt(3),x=-sqrt(3)