What are the solutions to the equation x^2+24x=-143 ?

The solutions to the equation x^2+24x=-143 are x=-11,x=-13

Find the zeros of x^2+24x=-143

The zeros of x^2+24x=-143 are x=-11,x=-13

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x^{2} + 24 x = - 143

x = - 11, x = - 13

Solution steps

x^{2} + 24 x = - 143

Move

143

to the left side

x^{2} + 24 x + 143 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 143}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 143 = 2

x_{1, 2} = \frac{- 24 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 2}{2 \cdot 1}, x_{2} = \frac{- 24 - 2}{2 \cdot 1}

x = \frac{- 24 + 2}{2 \cdot 1} : - 11

x = \frac{- 24 - 2}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 11, x = - 13

(3 a^{2} + x) 2 = 9 a^{4} + 24 a^{2} b^{2} + x^{2}

8 x^{2} - x - 1 = 0

4 x^{2} + 2 x

v^{2} = - 81

- 7 f + 4 f^{2} = - 2 f^{2} - f

What are the solutions to the equation x^2+24x=-143 ?
The solutions to the equation x^2+24x=-143 are x=-11,x=-13
Find the zeros of x^2+24x=-143
The zeros of x^2+24x=-143 are x=-11,x=-13