What are the solutions to the equation c^2-4c=0 ?

The solutions to the equation c^2-4c=0 are c=4,c=0

Find the zeros of c^2-4c=0

The zeros of c^2-4c=0 are c=4,c=0

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c^{2} - 4 c = 0

c = 4, c = 0

Solution steps

c^{2} - 4 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

c_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, c_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

c = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

c = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

c = 4, c = 0

(1 - 0.2) (\frac{0.2}{0.1})^{\frac{0.3}{0.7}}

5 + 7 a = 19

(r - 3) (r + 9) = - 16

2 x^{2} + 17 x + 15

\frac{7.68 \cdot 1 0 ^{- 4}}{2.4 \cdot 1 0 ^{2}}

What are the solutions to the equation c^2-4c=0 ?
The solutions to the equation c^2-4c=0 are c=4,c=0
Find the zeros of c^2-4c=0
The zeros of c^2-4c=0 are c=4,c=0