What are the solutions to the equation 2x^2-5x=x^2+3x ?

The solutions to the equation 2x^2-5x=x^2+3x are x=8,x=0

Find the zeros of 2x^2-5x=x^2+3x

The zeros of 2x^2-5x=x^2+3x are x=8,x=0

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2 x^{2} - 5 x = x^{2} + 3 x

x = 8, x = 0

Solution steps

2 x^{2} - 5 x = x^{2} + 3 x

Move

3 x

to the left side

2 x^{2} - 8 x = x^{2}

Move

x^{2}

to the left side

x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

x = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

2 n x^{2} + (n^{3} + 2) x = - n^{2}

x, H (t) = 0.004 x^{2} - 0.197 x + 5.406

x^{2} = - \frac{1}{3}

x^{2} + 4.8 x + 5.75 = 0

- 2 x^{2} + 4000 x = 0

What are the solutions to the equation 2x^2-5x=x^2+3x ?
The solutions to the equation 2x^2-5x=x^2+3x are x=8,x=0
Find the zeros of 2x^2-5x=x^2+3x
The zeros of 2x^2-5x=x^2+3x are x=8,x=0