What are the solutions to the equation x^2+10x-875=0 ?

The solutions to the equation x^2+10x-875=0 are x=25,x=-35

Find the zeros of x^2+10x-875=0

The zeros of x^2+10x-875=0 are x=25,x=-35

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x^{2} + 10 x - 875 = 0

x = 25, x = - 35

Solution steps

x^{2} + 10 x - 875 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 875 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 875) = 60

x_{1, 2} = \frac{- 10 \pm 60}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 60}{2 \cdot 1}, x_{2} = \frac{- 10 - 60}{2 \cdot 1}

x = \frac{- 10 + 60}{2 \cdot 1} : 25

x = \frac{- 10 - 60}{2 \cdot 1} : - 35

The solutions to the quadratic equation are:

x = 25, x = - 35

s^{2} + s + \frac{5}{4}

3 x^{2} = 4 x + 4

(3 a - 10) (2 a - 7) = 0

6 x^{2} + 8 x - 2 = 0

x^{2} - 8 x + 15 = 0

What are the solutions to the equation x^2+10x-875=0 ?
The solutions to the equation x^2+10x-875=0 are x=25,x=-35
Find the zeros of x^2+10x-875=0
The zeros of x^2+10x-875=0 are x=25,x=-35