What are the solutions to the equation x^2-8x=-3 ?

The solutions to the equation x^2-8x=-3 are x=4+sqrt(13),x=4-sqrt(13)

Find the zeros of x^2-8x=-3

The zeros of x^2-8x=-3 are x=4+sqrt(13),x=4-sqrt(13)

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x^{2} - 8 x = - 3

x = 4 + 13, x = 4 - 13

Decimal Notation

x = 7.60555 \dots, x = 0.39444 \dots

Solution steps

x^{2} - 8 x = - 3

Move

3

to the left side

x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 3 = 213

x_{1, 2} = \frac{- ( - 8 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 13}{2 \cdot 1} : 4 + 13

x = \frac{- ( - 8 ) - 2 13}{2 \cdot 1} : 4 - 13

The solutions to the quadratic equation are:

x = 4 + 13, x = 4 - 13

6 x^{2} + 11 b x = 10 b^{2}

t^{2} - t = 0

x^{2} - 12 x - 40 = 0

x, x^{2} - 4 x y + y^{2} = 0

w^{2} - 10 w + 21 = 0

What are the solutions to the equation x^2-8x=-3 ?
The solutions to the equation x^2-8x=-3 are x=4+sqrt(13),x=4-sqrt(13)
Find the zeros of x^2-8x=-3
The zeros of x^2-8x=-3 are x=4+sqrt(13),x=4-sqrt(13)