What is the answer to solvefor y,x^2-y+1=x-y+1 ?

The answer to solvefor y,x^2-y+1=x-y+1 is True for all y;\quad x^2=x

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solvefor y,x^2-y+1=x-y+1

solve for

y, x^{2} - y + 1 = x - y + 1

True for all y; x^{2} = x

Solution steps

x^{2} - y + 1 = x - y + 1

Subtract

- y + 1

from both sides

x^{2} - y + 1 - (- y + 1) = x - y + 1 - (- y + 1)

Simplify

x^{2} = x

Both sides are equal

True for all y; x^{2} = x

x, x^{2} + y^{2} + z^{2} - 4 z = 0

2 x^{2} - 18 x + 40 = 0

5 n^{2} - 30 = - 10

4 x^{2} + 8 = - 28

12 x^{2} - 36 x + 24 = 0

What is the answer to solvefor y,x^2-y+1=x-y+1 ?
The answer to solvefor y,x^2-y+1=x-y+1 is True for all y;\quad x^2=x