What are the solutions to the equation 20x=5x^2+20 ?

The solutions to the equation 20x=5x^2+20 are x=2

Find the zeros of 20x=5x^2+20

The zeros of 20x=5x^2+20 are x=2

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20 x = 5 x^{2} + 20

x = 2

Solution steps

20 x = 5 x^{2} + 20

Switch sides

5 x^{2} + 20 = 20 x

Move

20 x

to the left side

5 x^{2} + 20 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 20 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 20 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 5}

x = \frac{- ( - 20 )}{2 \cdot 5}

\frac{- ( - 20 )}{2 \cdot 5} = 2

x = 2

The solution to the quadratic equation is:

x = 2

3 (x + 5)^{2} = - 2

y, x^{3} - x y + y^{2} = 0

7 b^{2} + 14 b - 25 = - 4

x^{2} = 5^{2} + 6^{2}

3 x^{2} + 7 x + 6 = 0

What are the solutions to the equation 20x=5x^2+20 ?
The solutions to the equation 20x=5x^2+20 are x=2
Find the zeros of 20x=5x^2+20
The zeros of 20x=5x^2+20 are x=2