What are the solutions to the equation 4x^2-80x+356=0 ?

The solutions to the equation 4x^2-80x+356=0 are x=10+sqrt(11),x=10-sqrt(11)

Find the zeros of 4x^2-80x+356=0

The zeros of 4x^2-80x+356=0 are x=10+sqrt(11),x=10-sqrt(11)

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4 x^{2} - 80 x + 356 = 0

x = 10 + 11, x = 10 - 11

Decimal Notation

x = 13.31662 \dots, x = 6.68337 \dots

Solution steps

4 x^{2} - 80 x + 356 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 4 \cdot 356}{2 \cdot 4}

(- 80)^{2} - 4 \cdot 4 \cdot 356 = 811

x_{1, 2} = \frac{- ( - 80 ) \pm 8 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 8 11}{2 \cdot 4}, x_{2} = \frac{- ( - 80 ) - 8 11}{2 \cdot 4}

x = \frac{- ( - 80 ) + 8 11}{2 \cdot 4} : 10 + 11

x = \frac{- ( - 80 ) - 8 11}{2 \cdot 4} : 10 - 11

The solutions to the quadratic equation are:

x = 10 + 11, x = 10 - 11

(2 - 3 x)^{2} = x + 1

(x + 6)^{2} = 121

(x + 6)^{2} = 144

1600 = 85 x - 150 - x^{2}

2 x^{2} = 32 x

What are the solutions to the equation 4x^2-80x+356=0 ?
The solutions to the equation 4x^2-80x+356=0 are x=10+sqrt(11),x=10-sqrt(11)
Find the zeros of 4x^2-80x+356=0
The zeros of 4x^2-80x+356=0 are x=10+sqrt(11),x=10-sqrt(11)