What are the solutions to the equation 16x^2-24x+13=4 ?

The solutions to the equation 16x^2-24x+13=4 are x= 3/4

Find the zeros of 16x^2-24x+13=4

The zeros of 16x^2-24x+13=4 are x= 3/4

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16 x^{2} - 24 x + 13 = 4

x = \frac{3}{4}

Decimal

x = 0.75

Solution steps

16 x^{2} - 24 x + 13 = 4

Move

4

to the left side

16 x^{2} - 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 24 )}{2 \cdot 16}

\frac{- ( - 24 )}{2 \cdot 16} = \frac{3}{4}

x = \frac{3}{4}

The solution to the quadratic equation is:

x = \frac{3}{4}

8 x^{2} + 63 = - 46 x

6 x^{2} - 6 x + 3 = 0

3 u^{2} = 24 u - 6

m^{2} x^{2} + 2 m x + 1 - n^{2} = 0

a^{2} + 5^{2} = 1 0^{2}

What are the solutions to the equation 16x^2-24x+13=4 ?
The solutions to the equation 16x^2-24x+13=4 are x= 3/4
Find the zeros of 16x^2-24x+13=4
The zeros of 16x^2-24x+13=4 are x= 3/4