What are the solutions to the equation x^2+12x=64 ?

The solutions to the equation x^2+12x=64 are x=4,x=-16

Find the zeros of x^2+12x=64

The zeros of x^2+12x=64 are x=4,x=-16

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x^{2} + 12 x = 64

x = 4, x = - 16

Solution steps

x^{2} + 12 x = 64

Move

64

to the left side

x^{2} + 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 64) = 20

x_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 20}{2 \cdot 1}, x_{2} = \frac{- 12 - 20}{2 \cdot 1}

x = \frac{- 12 + 20}{2 \cdot 1} : 4

x = \frac{- 12 - 20}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 4, x = - 16

64 - x^{2} = 0

x (x + 8) = 2900

x, - x^{2} - 2 m x = - 20 + 2 m x

x, z = x^{2} + 3 y^{2}

x, x^{2} + y^{2} + 2 y + 1 = 0

What are the solutions to the equation x^2+12x=64 ?
The solutions to the equation x^2+12x=64 are x=4,x=-16
Find the zeros of x^2+12x=64
The zeros of x^2+12x=64 are x=4,x=-16