What are the solutions to the equation (x+1)^2=-25 ?

The solutions to the equation (x+1)^2=-25 are x=5i-1,x=-5i-1

Find the zeros of (x+1)^2=-25

The zeros of (x+1)^2=-25 are x=5i-1,x=-5i-1

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(x + 1)^{2} = - 25

x = 5 i - 1, x = - 5 i - 1

Solution steps

(x + 1)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 25 : x = 5 i - 1

Solve

x + 1 = - - 25 : x = - 5 i - 1

The solutions to the quadratic equation are:

x = 5 i - 1, x = - 5 i - 1

x^{2} = 2 - x^{2}

x, x^{2} + x y - y^{2} = - 1

4 x^{2} - 3 = 25

- 7 (x - 2)^{2} - 14 = 0

x^{2} + 2 x + 5 = 0

What are the solutions to the equation (x+1)^2=-25 ?
The solutions to the equation (x+1)^2=-25 are x=5i-1,x=-5i-1
Find the zeros of (x+1)^2=-25
The zeros of (x+1)^2=-25 are x=5i-1,x=-5i-1