What are the solutions to the equation (x+4)^2=20 ?

The solutions to the equation (x+4)^2=20 are x=2sqrt(5)-4,x=-2sqrt(5)-4

Find the zeros of (x+4)^2=20

The zeros of (x+4)^2=20 are x=2sqrt(5)-4,x=-2sqrt(5)-4

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(x + 4)^{2} = 20

x = 25 - 4, x = - 25 - 4

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

(x + 4)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 20 : x = 25 - 4

Solve

x + 4 = - 20 : x = - 25 - 4

The solutions to the quadratic equation are:

x = 25 - 4, x = - 25 - 4

5 x^{2} + 6 x + 4 = 0

27 x^{2} - 27 = 0

(14 - 2 x) (20 - 2 x) = 108

x^{2} + (7 - x) 2 = 30

x^{2} - 2 (x + 1) = 0

What are the solutions to the equation (x+4)^2=20 ?
The solutions to the equation (x+4)^2=20 are x=2sqrt(5)-4,x=-2sqrt(5)-4
Find the zeros of (x+4)^2=20
The zeros of (x+4)^2=20 are x=2sqrt(5)-4,x=-2sqrt(5)-4