What are the solutions to the equation 4x^2-4x+16=0 ?

The solutions to the equation 4x^2-4x+16=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

Find the zeros of 4x^2-4x+16=0

The zeros of 4x^2-4x+16=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

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4 x^{2} - 4 x + 16 = 0

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

Solution steps

4 x^{2} - 4 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 16}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 16 : 415 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4 15 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4 15 i}{2 \cdot 4} : \frac{1}{2} + i \frac{15}{2}

x = \frac{- ( - 4 ) - 4 15 i}{2 \cdot 4} : \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

3 x^{2} + 12 x + 7

x^{2} + 21 = 7 x

a, a^{2} + a = b^{2} + b

9 x - x^{2} - 14 = 0

x^{2} + 5 = 17

What are the solutions to the equation 4x^2-4x+16=0 ?
The solutions to the equation 4x^2-4x+16=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2
Find the zeros of 4x^2-4x+16=0
The zeros of 4x^2-4x+16=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2