What are the solutions to the equation 3x^2+113x-7=0 ?

The solutions to the equation 3x^2+113x-7=0 are x=(-113+sqrt(12853))/6 ,x=(-113-sqrt(12853))/6

Find the zeros of 3x^2+113x-7=0

The zeros of 3x^2+113x-7=0 are x=(-113+sqrt(12853))/6 ,x=(-113-sqrt(12853))/6

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3 x^{2} + 113 x - 7 = 0

x = \frac{- 113 + 12853}{6}, x = \frac{- 113 - 12853}{6}

Decimal Notation

x = 0.06184 \dots, x = - 37.72851 \dots

Solution steps

3 x^{2} + 113 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 113 \pm 11 3 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

11 3^{2} - 4 \cdot 3 (- 7) = 12853

x_{1, 2} = \frac{- 113 \pm 12853}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 113 + 12853}{2 \cdot 3}, x_{2} = \frac{- 113 - 12853}{2 \cdot 3}

x = \frac{- 113 + 12853}{2 \cdot 3} : \frac{- 113 + 12853}{6}

x = \frac{- 113 - 12853}{2 \cdot 3} : \frac{- 113 - 12853}{6}

The solutions to the quadratic equation are:

x = \frac{- 113 + 12853}{6}, x = \frac{- 113 - 12853}{6}

3 x^{2} - 7 + 2 = 0

4 x^{2} - 11 = 14

2 - 2 x^{2} = 0

x^{2} + 4 x = 8

y^{2}

What are the solutions to the equation 3x^2+113x-7=0 ?
The solutions to the equation 3x^2+113x-7=0 are x=(-113+sqrt(12853))/6 ,x=(-113-sqrt(12853))/6
Find the zeros of 3x^2+113x-7=0
The zeros of 3x^2+113x-7=0 are x=(-113+sqrt(12853))/6 ,x=(-113-sqrt(12853))/6