What are the solutions to the equation 16x(x-2)=8x-25 ?

The solutions to the equation 16x(x-2)=8x-25 are x= 5/4

Find the zeros of 16x(x-2)=8x-25

The zeros of 16x(x-2)=8x-25 are x= 5/4

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16 x (x - 2) = 8 x - 25

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

16 x (x - 2) = 8 x - 25

Expand

16 x (x - 2) : 16 x^{2} - 32 x

16 x^{2} - 32 x = 8 x - 25

Move

25

to the left side

16 x^{2} - 32 x + 25 = 8 x

Move

8 x

to the left side

16 x^{2} - 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

x = \frac{5}{4}

The solution to the quadratic equation is:

x = \frac{5}{4}

6 x^{2} + 12 x - 144 = 0

16 = - t^{2} + 10 t

- 3 x^{2} + 5 x + 1 = 0

d^{2} + 11 = 0

- 4 x^{2} - 11 x + 3 = 0

What are the solutions to the equation 16x(x-2)=8x-25 ?
The solutions to the equation 16x(x-2)=8x-25 are x= 5/4
Find the zeros of 16x(x-2)=8x-25
The zeros of 16x(x-2)=8x-25 are x= 5/4