What are the solutions to the equation 2x^2-9x-17=0 ?

The solutions to the equation 2x^2-9x-17=0 are x=(9+sqrt(217))/4 ,x=(9-sqrt(217))/4

Find the zeros of 2x^2-9x-17=0

The zeros of 2x^2-9x-17=0 are x=(9+sqrt(217))/4 ,x=(9-sqrt(217))/4

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2 x^{2} - 9 x - 17 = 0

x = \frac{9 + 217}{4}, x = \frac{9 - 217}{4}

Decimal Notation

x = 5.93272 \dots, x = - 1.43272 \dots

Solution steps

2 x^{2} - 9 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 17 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 17) = 217

x_{1, 2} = \frac{- ( - 9 ) \pm 217}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 217}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 217}{2 \cdot 2}

x = \frac{- ( - 9 ) + 217}{2 \cdot 2} : \frac{9 + 217}{4}

x = \frac{- ( - 9 ) - 217}{2 \cdot 2} : \frac{9 - 217}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 217}{4}, x = \frac{9 - 217}{4}

x^{2} + 4 x = - 2

2.2 5^{2}

27 x^{3} - y^{3}

(x + 3)^{2} = - 16

x - (3 - x) = 7 - (x + 2)

What are the solutions to the equation 2x^2-9x-17=0 ?
The solutions to the equation 2x^2-9x-17=0 are x=(9+sqrt(217))/4 ,x=(9-sqrt(217))/4
Find the zeros of 2x^2-9x-17=0
The zeros of 2x^2-9x-17=0 are x=(9+sqrt(217))/4 ,x=(9-sqrt(217))/4